How many solutions does this have:
x^2 + 2x + 1 = 0
I put one.
9x^2 + 49 = 42x
I put one.
x^2 + 4x + 1 = 0
I put two.
5 answers
I actually think the 2nd one has no real solutions...
nah, you are correct on all three
9x^2 - 42x + 49 = 0
(3x-7)^2 = 0
9x^2 - 42x + 49 = 0
(3x-7)^2 = 0
Ok cool! you think you can show me how to do these?
1. What is the largest output value of f(x) possible for the following quadratic function? f(x) = - x 2 -6 x + 15.
2. What is the absolute value of the smallest output value of f(x) possible for the following quadratic function? f(x) = x 2 – 2 x - 8
1. What is the largest output value of f(x) possible for the following quadratic function? f(x) = - x 2 -6 x + 15.
2. What is the absolute value of the smallest output value of f(x) possible for the following quadratic function? f(x) = x 2 – 2 x - 8
as you know, the vertex of the parabola
y = ax^2 + bx + c
is at x = -b/2a
#1 the parabola opens down, so the vertex is a maximum
#2 has a minimum at the vertex
so, plug in that value for x and let 'er rip
y = ax^2 + bx + c
is at x = -b/2a
#1 the parabola opens down, so the vertex is a maximum
#2 has a minimum at the vertex
so, plug in that value for x and let 'er rip
I have no idea what any of that means... :)