Asked by Dustin
What mass in grams of potassium hydroxide is contained in 500 mL of solution that has a pH of 11.5?
I have a pOH of 2.5
to get [OH]
I do 10^-2.5 to get 0.001581138
Then I divide this by 2 to find the mols in 500 mL
Then, grams = mols x molar mass
= 0.00158``38 x 56.105 g/mol
=0.08 g
Why is my answer wrong?
I have a pOH of 2.5
to get [OH]
I do 10^-2.5 to get 0.001581138
Then I divide this by 2 to find the mols in 500 mL
Then, grams = mols x molar mass
= 0.00158``38 x 56.105 g/mol
=0.08 g
Why is my answer wrong?
Answers
Answered by
DrBob222
What mass in grams of potassium hydroxide is contained in 500 mL of solution that has a pH of 11.5?
I have a pOH of 2.5 <b> OK</b>
to get [OH]
I do 10^-2.5 to get 0.001581138
<b>No, (OH^-) = 0.00316 M </b>
Then I divide this by 2 to find the mols in 500 mL
<b> 0.00316/2 = 0.00158 mols in 500 mL.</b>
Then, grams = mols x molar mass
= 0.00158``38 x 56.105 g/mol
<b>I don't know what the ``38 is. Also, you took 0.00158, divided by 2 and still came out with 0.00158? I think you lost track of what you were typing here. 0.00158 mol in 500 is the correct number. </b>
=0.08 g
<b> 0.00158 mols x 56.105 g/mol = 0.08865 g which I would round to 0.0886 g KOH.</b>
Why is my answer wrong? <b>My best guess is that you truncated the number to 0.08 g instead of keeping the other two places of 0.0886 g</b> Check my work.
I have a pOH of 2.5 <b> OK</b>
to get [OH]
I do 10^-2.5 to get 0.001581138
<b>No, (OH^-) = 0.00316 M </b>
Then I divide this by 2 to find the mols in 500 mL
<b> 0.00316/2 = 0.00158 mols in 500 mL.</b>
Then, grams = mols x molar mass
= 0.00158``38 x 56.105 g/mol
<b>I don't know what the ``38 is. Also, you took 0.00158, divided by 2 and still came out with 0.00158? I think you lost track of what you were typing here. 0.00158 mol in 500 is the correct number. </b>
=0.08 g
<b> 0.00158 mols x 56.105 g/mol = 0.08865 g which I would round to 0.0886 g KOH.</b>
Why is my answer wrong? <b>My best guess is that you truncated the number to 0.08 g instead of keeping the other two places of 0.0886 g</b> Check my work.
Answered by
Ross
Wow , thanks you are a really excellent expert!
:)
:)
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