Asked by Jennifer W.
The area of a rectangular painting is given by the trinomial x2 + 4x – 21. What are the possible dimensions of the painting? Use factoring.
Options: x + 7 and x + 3
x – 7 and x + 3
x – 7 and x – 3
x + 7 and x – 3
Options: x + 7 and x + 3
x – 7 and x + 3
x – 7 and x – 3
x + 7 and x – 3
Answers
Answered by
Steve
since
x^2+4x-21 = (x+7)(x-3)
Looks like (d)
x^2+4x-21 = (x+7)(x-3)
Looks like (d)
Answered by
♥𝕤𝕥𝕣𝕒𝕨𝕓𝕖𝕣𝕣𝕪 𝕓𝕒𝕓𝕪♥
thank you steve!
Answered by
Alex
Love you Steve UwU <3
Answered by
NarutoUzi
good stuff my brother
Answered by
Sasuchi
ez thx steve
Answered by
baba
The area of a rectangular painting is given by the trinomial x2 – 5x – 36. What are the possible dimensions of the painting? Use factoring.
A. (x + 9) and (x – 4)
B. (x + 9) and (x + 4)
C. (x – 9) and (x – 4)
D. (x – 9) and (x + 4)
A. (x + 9) and (x – 4)
B. (x + 9) and (x + 4)
C. (x – 9) and (x – 4)
D. (x – 9) and (x + 4)
Answered by
baba
Graph the function and identify the domain and range.
y = –6x2
A. graph
domain: (–∞,∞)
range: y ≤ 0
B. graph
domain: (–∞,∞)
range: y ≥ 0
C. graph
domain: (–∞,∞)
range: y ≥ 0
D. graph
domain: (–∞,∞)
range: y ≥ 0
7 / 32
y = –6x2
A. graph
domain: (–∞,∞)
range: y ≤ 0
B. graph
domain: (–∞,∞)
range: y ≥ 0
C. graph
domain: (–∞,∞)
range: y ≥ 0
D. graph
domain: (–∞,∞)
range: y ≥ 0
7 / 32
Answered by
Bot
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Answered by
Bot
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Answered by
Bot
The area of the painting is given by the trinomial x^2 - 5x - 36, which can be factored as (x - 9)(x + 4).
Therefore, the possible dimensions of the painting are (x - 9) and (x + 4).
The answer is option D.
Therefore, the possible dimensions of the painting are (x - 9) and (x + 4).
The answer is option D.
Answered by
Bot
The graph of the function y = -6x^2 is a downward-opening parabola with its vertex at the origin (0,0).
The domain is all real numbers because there are no restrictions on the values that x can take. So the domain is (–∞,∞).
The range, however, is limited by the fact that the square of any real number is non-negative. Therefore, y can take on any negative number or 0, but it cannot be positive.
So the answer is A.
Here's a rough sketch of the graph:

The domain is all real numbers because there are no restrictions on the values that x can take. So the domain is (–∞,∞).
The range, however, is limited by the fact that the square of any real number is non-negative. Therefore, y can take on any negative number or 0, but it cannot be positive.
So the answer is A.
Here's a rough sketch of the graph:

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