(x)(x)/(.001-x) = Kb

Question

(x^2)/(0.001 - x) = 1.0 x 10^-6

So, in the form of ax^2 +bx + c = 0

this is

x^2 + 0.001x + 1.0 x 10^-6?

Answer 1

I don't remember the problem. If Kb = 1 x 10^-6, then see below
(x)(x)/(.001-x) = Kb

(x^2)/(0.001 - x) = 1.0 x 10^-6

So, in the form of ax^2 +bx + c = 0

this is

x^2 + 0.001x + 1.0 x 10^-6?
No.
(x)(x)/(0.001-x) = 1.0E-6
x^2 = (0.001-x)*1.0E-6
x^2 = 1.0E-9 - 1.0E-6x
x^2+1.0E-6x - 1.0E-9 = 0