Asked by Dustin
(x)(x)/(.001-x) = Kb
(x^2)/(0.001 - x) = 1.0 x 10^-6
So, in the form of ax^2 +bx + c = 0
this is
x^2 + 0.001x + 1.0 x 10^-6?
(x^2)/(0.001 - x) = 1.0 x 10^-6
So, in the form of ax^2 +bx + c = 0
this is
x^2 + 0.001x + 1.0 x 10^-6?
Answers
Answered by
DrBob222
<b>I don't remember the problem. If Kb = 1 x 10^-6, then see below</b>
(x)(x)/(.001-x) = Kb
(x^2)/(0.001 - x) = 1.0 x 10^-6
So, in the form of ax^2 +bx + c = 0
this is
x^2 + 0.001x + 1.0 x 10^-6?
<b>No.
(x)(x)/(0.001-x) = 1.0E-6
x^2 = (0.001-x)*1.0E-6
x^2 = 1.0E-9 - 1.0E-6x
x^2+1.0E-6x - 1.0E-9 = 0
</b>
(x)(x)/(.001-x) = Kb
(x^2)/(0.001 - x) = 1.0 x 10^-6
So, in the form of ax^2 +bx + c = 0
this is
x^2 + 0.001x + 1.0 x 10^-6?
<b>No.
(x)(x)/(0.001-x) = 1.0E-6
x^2 = (0.001-x)*1.0E-6
x^2 = 1.0E-9 - 1.0E-6x
x^2+1.0E-6x - 1.0E-9 = 0
</b>
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