Asked by Anonymous

Suppose that 2.00 moles of HCl in a 1.00L glass flask slowly decomposes into H2 and Cl2. When equilibrim is reached, the concentrations of H2 and Cl2 are both 0.214M. What is the Keq?

Answers

Answered by unknown
Keq = product/ reactant
Write the balanced equation for what you are given. 2HCl--->H2 + Cl2

I believe that's how you start off.
Answered by DrBob222
.........2HCl ==> H2 + Cl2
I........2M........0.....0
C........-2x.......x.....x
E.......2-2x.....0.214..0.214

Therefore, at equilibrium, H2 = 0.214, Cl2 = 0.214 and HCl = 2-2*0.214. Substitute into Keq expression and evaluate for Keq.
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