Asked by silent_klr
A box weighting 200N is pushed on a horizontal floor. What acceleration will result if a horizontal force of 100N is applied to the box.? coefficient of friction is 0.4
Answers
Answered by
drwls
The friction force in the reverse direction is 200*0.4 = 80 N.
The net forward force acting on the box is therefore
Fnet = 100 - 80 = 20 N
Acceleration = Fnet/Mass = Fnet*g/(Weight)
= 20*9.8/200 = 0.98 m/s^2
The net forward force acting on the box is therefore
Fnet = 100 - 80 = 20 N
Acceleration = Fnet/Mass = Fnet*g/(Weight)
= 20*9.8/200 = 0.98 m/s^2
Answered by
silent_klr
Thanks. I have also done the same solution. Just confirming it. Thanks!
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