Starting from rest, a skier slides 100 m down a 28 degree slope.How much longer does the run take if the coefficient of kinetic friction is 0.17 instead of 0?

Answer 1

Case 1: zero friction
F=mg sin(28)
a=F/m=g sin(28)
S=ut+(1/2)at²
100=0+g sin(28)t²/2
t=sqrt(2*100/(g sin(28))
=6.59 s.

Case 2: μ_k=0.17
Frictional force
=μmg cos(28)
Net force (assuming μcos<sin)
=mg(sin(28)-μcos(28)
t=sqrt(2*100/(g (sin(28)-μcos(28))
=7.99 s

Take the difference.

Answer 2

shouldn't case 1 be cos(28) lol

Answer 3

I didn't understand where the net force equation in case 2 came from

Answer 4

nvm I got it