The closest point (x0,y0) on the circle to point (x1,y1) of the circle is if (x0,y0) lies on the radial line passing through (x1,y1).
To show this, first find the centre of the circle x^2+y^2=1 is a circle with radius 1 and centre (0,0).
The line through (0,0) and (3,4) is
L : y=(4/3)x (slope=(4-0)/(3-0)=4/3, and y-intercept=0)
Show that the point P(3/5,4/5) is on the line L as follows:
y=(4/3)x=(4/3)(3/5)=4/5 which equals the y-coordinate of the point P. So P lies on line L, thus (3/5,4/5) lies on the circle and is the closest point to (3/4)
show that the point (3/5, 4/5) is the closest point on the circle x^2 + y^2= 1 to the point on (3,4)
how do ido this
2 answers
you have a mystery number greater than 10 and less than 60 It has a remainder of 1 when divided by 6 and a remainder of 2 when divided by 5 what is the mystery number
1 answer