Asked by thomas
wtite 3x^2 +8x-25 in the fomr a(x+h)^2+k, where a,h and k are real numbers
Answers
Answered by
Reiny
3x^2 +8x-25
= 3[x^2 + (8/3)x <b>+ 16/9 - 16/9</b>] - 25
= 3[(x+4/3)^2 - 16/9] -25
= 3(x+4/3)^2 - 16/3 - 25
= 3(x+4/3)2 - 91/3
= 3[x^2 + (8/3)x <b>+ 16/9 - 16/9</b>] - 25
= 3[(x+4/3)^2 - 16/9] -25
= 3(x+4/3)^2 - 16/3 - 25
= 3(x+4/3)2 - 91/3
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