Asked by seth
A yo-yo with an axle diameter of 2.00cm has a 80.0cm length of string wrapped around it many times in such a way that the string completely covers the surface of its axle, but there are no double layers of string. The outermost portion of the yo-yo is 4.00 {\rm cm} from the center of the axle.If the yo-yo is dropped with the string fully wound, through what angle does it rotate by the time it reaches the bottom of its fall?
Answers
Answered by
Elena
The circumference of the axel is
L=πd,
the string wraps around the axel
N=s/L= s/ πd.
The angle of rotation is
φ=2πN=2 πs/ πd=2s/d= =2•80/2=80 rad
L=πd,
the string wraps around the axel
N=s/L= s/ πd.
The angle of rotation is
φ=2πN=2 πs/ πd=2s/d= =2•80/2=80 rad
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