Asked by Ann
Edna has scored in 80% of the games she's played.What is the probability she woulds score a goal in at least 7 out of her 8 games. P (if she scored in 3 or 4 games, what is the probability that she scores in exactly 4).?
Answers
Answered by
MathMate
p=probability of scoring (success) = 0.8
q=probability of not scoring (failure = 0.2
Assuming the probability does not change over time and is independent of previous results, then we can apply the binomial distribution:
P(7+ out of 8)
=8C7*0.8^70.2+8C80.8^8
=0.34+.17
=0.50 (approx.)
Please explain the part of the question in parentheses... "scored in 3 <i>or</i> 4 games..." How many did she play?
q=probability of not scoring (failure = 0.2
Assuming the probability does not change over time and is independent of previous results, then we can apply the binomial distribution:
P(7+ out of 8)
=8C7*0.8^70.2+8C80.8^8
=0.34+.17
=0.50 (approx.)
Please explain the part of the question in parentheses... "scored in 3 <i>or</i> 4 games..." How many did she play?
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