Asked by scott
If a metal wire carries a current of 79
.
0 mA,
how long does it take for 7.90
×
10
20
electrons
to pass a given cross-sectional area anywhere
along the wire? The fundamental charge is
1
.
602
×
10
−
19
C.
Answer in units of s
.
0 mA,
how long does it take for 7.90
×
10
20
electrons
to pass a given cross-sectional area anywhere
along the wire? The fundamental charge is
1
.
602
×
10
−
19
C.
Answer in units of s
Answers
Answered by
bobpursley
1 amp=1coulomb/sec=1coulomb/e electrons per second
1amp=1/1.603E-19 electrons/sec
= 6.24E18 electrons per second.
so then 79ma=.079amp=.079*6.24E18 electrons/sec
time=electcrons/rate=7.90E20/.079*6.24E18
time=1603seconds
check all that
1amp=1/1.603E-19 electrons/sec
= 6.24E18 electrons per second.
so then 79ma=.079amp=.079*6.24E18 electrons/sec
time=electcrons/rate=7.90E20/.079*6.24E18
time=1603seconds
check all that
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