Draw a rhombus, and mark one side as 24 cm, and one of the diagonals as 24 cm long. Then the half diagonal is 12 cm.
Since the diagonals of a rhombus intersect at right angles, we have a right-triangle with hypotenuse 14 cm, with one side as 12. The other half-diagonal is therefore
sqrt(14²-12²)=sqrt(52).
The area of a rhombus is the product of the diagonals (24 cm and 2sqrt(52)) divided by 2.
A rhombus has a side that is 14cm long. One of its diagonals is 24cm long. What is the area?
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