Asked by parker
how many liters of oxygen are necessary for the combustion of 340 g of ethanol (c2h5OH) assuming the raction occurs at STP? no idea how to work this out
Answers
Answered by
bobpursley
write the equation:
7O2 + 2C2H5OH>>4CO2 + 6H2O
check that.
so the moles of O2 is 3.5 x moles ethanol.
figure the moles of ethanol, then the moles of oxygen,then multiply by 22.4
7O2 + 2C2H5OH>>4CO2 + 6H2O
check that.
so the moles of O2 is 3.5 x moles ethanol.
figure the moles of ethanol, then the moles of oxygen,then multiply by 22.4
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