Asked by Pebble

A gambling game pays 4 to 1 and the chance of winning is 1 in 6. Suppose you bet $1 on this game 600 times independently.

3A Find the expected number of times you win.

3B Find the SE of the number of times you win.

3C Find the chance that you lose more than $50 (that is, your net gain in the 600 bets is less than -$50).


Answers

Answered by BK
a) 0.342
b) 0.231
c) 0.625
Answered by BK
honor code
Answered by L13
a) 100

1/6*600=100
Answered by L13
b) 9.1287
sqrt(n*p*(1-p))
sqrt(600*1/6*(5/6))=9.1287
Answered by Din123
a) 0.342
b) 0.231
c) 0.625

all are wrong!

a) 100
b) 9.1287

Correct! Thank you very much L13!
Answered by Anonymous
-50=4X-(600-X)
600-50=550=5X
X=110
So, 86.33394%
Answered by Anonymous
Sorry, 0.851
Answered by seriously
LOL. And you twerps really think a mooc certificate is going to get you a job or uni credit.
Answered by skeptical
can't believe this. honor code!
Answered by Anonymous
Why do you care?
Answered by Help
a)100
b)9.1287
c)0.851
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