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A gambling game pays 4 to 1 and the chance of winning is 1 in 6. Suppose you bet $1 on this game 600 times independently. 3A -...Asked by Pebble
A gambling game pays 4 to 1 and the chance of winning is 1 in 6. Suppose you bet $1 on this game 600 times independently.
3A Find the expected number of times you win.
3B Find the SE of the number of times you win.
3C Find the chance that you lose more than $50 (that is, your net gain in the 600 bets is less than -$50).
3A Find the expected number of times you win.
3B Find the SE of the number of times you win.
3C Find the chance that you lose more than $50 (that is, your net gain in the 600 bets is less than -$50).
Answers
Answered by
BK
a) 0.342
b) 0.231
c) 0.625
b) 0.231
c) 0.625
Answered by
BK
honor code
Answered by
L13
a) 100
1/6*600=100
1/6*600=100
Answered by
L13
b) 9.1287
sqrt(n*p*(1-p))
sqrt(600*1/6*(5/6))=9.1287
sqrt(n*p*(1-p))
sqrt(600*1/6*(5/6))=9.1287
Answered by
Din123
a) 0.342
b) 0.231
c) 0.625
all are wrong!
a) 100
b) 9.1287
Correct! Thank you very much L13!
b) 0.231
c) 0.625
all are wrong!
a) 100
b) 9.1287
Correct! Thank you very much L13!
Answered by
Anonymous
-50=4X-(600-X)
600-50=550=5X
X=110
So, 86.33394%
600-50=550=5X
X=110
So, 86.33394%
Answered by
Anonymous
Sorry, 0.851
Answered by
seriously
LOL. And you twerps really think a mooc certificate is going to get you a job or uni credit.
Answered by
skeptical
can't believe this. honor code!
Answered by
Anonymous
Why do you care?
Answered by
Help
a)100
b)9.1287
c)0.851
b)9.1287
c)0.851
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