Asked by Anonymous
¬Calculate the period of oscillation of a simple pendulum of length 1.8 m, with a bob of mass 2.2 kg. What assumption is made in this calculation?
(g = 9.8 m s - 2)
If the bob of this pendulum is pulled aside a horizontal distance of 20cm and
released, what will be the values of (i) the kinetic energy and (ii) the velocity of the bob at the lowest point of the swing?
(g = 9.8 m s - 2)
If the bob of this pendulum is pulled aside a horizontal distance of 20cm and
released, what will be the values of (i) the kinetic energy and (ii) the velocity of the bob at the lowest point of the swing?
Answers
Answered by
Henry
T^2 = 4*pi^2(L/g)
T^2 = 39.48(1.8/9.8) = 7.25
T = 2.69 s.
T^2 = 39.48(1.8/9.8) = 7.25
T = 2.69 s.