Lim (10x - cosx + 1)/(sinx + x)

(x->0)

4 answers

Lim (10x - cosx + 1)/(sinx + x)
= Lim (10 + sinx)/(cosx + 1)
= 10/2
= 5
how did you do this?
(10x - cosx + 1)/(sinx + x)
= (10 + sinx)/(cosx + 1)
remember L'Hospital's Rule:

lim f(x)/g(x) = lim f'(x)/g'(x)

when you are dealing with 0/0 or ∞/∞
Thanks :)))