Asked by Anonymous
A car traveling at 80km/hr decelerates at 1.5m/s^2. Calculate
a) the time it takes to stop.
b) The distance travelled in the 3rd second.
a) the time it takes to stop.
b) The distance travelled in the 3rd second.
Answers
Answered by
bobpursley
a. Vf=Vi-at solve for t.
b. find distance at t=3, then distance at t=4 and subtract
d=vi+at where t=3, then do it for t=4
b. find distance at t=3, then distance at t=4 and subtract
d=vi+at where t=3, then do it for t=4
Answered by
bobpursley
convert 80km/hr to m/s first.
Answered by
Adil
b)
d=vi+at
d=22.22+1.5+3=26.72
d=22.22+1.5+4=27.72
d=27.72-26.72
d=1
is it correct for
d=vi+at
d=22.22+1.5+3=26.72
d=22.22+1.5+4=27.72
d=27.72-26.72
d=1
is it correct for
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