if you have a bag of chocolate candy, ten are red, 7 are brown, 12 are green, and 9 are blue, what is the probability of you picking a red candy given that you already picked a blue candy and have not replaced it?

Answer 1

10 + 7 + 12 + 8 = 37

10/37 = 0.27 = 27%

Answer 2

10/37

Answer 3

the actual answer is 9/37