If the EMF produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of strength 0.075 newtons/amp·meter at a speed of 4.20 meters/second, what is the length of the wire in the magnetic field?

Answer 1

Use the formula

E.M.F. = L*B*V , where

B = 0.075 Tesla (or N/amp*m)
EMF = 0.88 Volts
V = 4.2 m/s
Solve for L

L = 2.8 m