Asked by Jake
If the EMF produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of strength 0.075 newtons/amp·meter at a speed of 4.20 meters/second, what is the length of the wire in the magnetic field?
Answers
Answered by
drwls
Use the formula
E.M.F. = L*B*V , where
B = 0.075 Tesla (or N/amp*m)
EMF = 0.88 Volts
V = 4.2 m/s
Solve for L
L = 2.8 m
E.M.F. = L*B*V , where
B = 0.075 Tesla (or N/amp*m)
EMF = 0.88 Volts
V = 4.2 m/s
Solve for L
L = 2.8 m
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