A)
The two digits can be arranged in 10x10 or 100 ways
B) Assuming that KRIS must remain that way, there would be 100 such plates,
e.g KRIS56 is one of them
Part A: How many different ways can the two digits be arranged?
Part B: Suppose the plate has KRIS followed by two additional digits. How many different plates of this type are there?
The two digits can be arranged in 10x10 or 100 ways
B) Assuming that KRIS must remain that way, there would be 100 such plates,
e.g KRIS56 is one of them
= 2 * 1
= 2 different possible ways
I mean, just think about the question. If the digits follow the letters KRIS, how can you arrange them in a hundred different ways? Let's say the numbers are 5 and 6. You can arrange them either 5,6 or 6,5. You can't arrange them 100 different ways.
Not sure about Part B though... I don't even understand what it's asking.
Part A: The digits can be arranged in two ways, so we need to calculate 10 options for the first digit multiplied by 10 options for the second digit. This gives us a total of 10 * 10 = 100 different ways to arrange the two digits.
To calculate the number of different plates of type KRIS followed by two additional digits, we can use the same logic as in Part A.
Part B: The first letter "K" of KRIS is fixed, so we have 1 option for the first letter. For the remaining three letters "RIS," we do not have any restrictions, so we have 26 options for each of them (assuming we consider only uppercase letters of the English alphabet). Finally, the two digits can be chosen from the numbers 0 to 9, as discussed in Part A.
Considering all these combinations, we have 1 * 26 * 26 * 26 * 10 * 10 = 1,757,600 different plates of type KRIS followed by two additional digits.