Kris wants to order a personalized license plate for her car. The plate is to have the 4 letters KRIS followed by any two digits.

A)

The two digits can be arranged in 10x10 or 100 ways

B) Assuming that KRIS must remain that way, there would be 100 such plates,
e.g KRIS56 is one of them

how is it 100 ways?

I'm not sure, but shouldn't the answer for Part A be 2!

= 2 * 1
= 2 different possible ways

I mean, just think about the question. If the digits follow the letters KRIS, how can you arrange them in a hundred different ways? Let's say the numbers are 5 and 6. You can arrange them either 5,6 or 6,5. You can't arrange them 100 different ways.

Not sure about Part B though... I don't even understand what it's asking.

I misunderstood completely, don't take my answer into account xD

To calculate the number of different ways the two digits can be arranged, we need to consider that each digit can be chosen from the numbers 0 to 9.

Part A: The digits can be arranged in two ways, so we need to calculate 10 options for the first digit multiplied by 10 options for the second digit. This gives us a total of 10 * 10 = 100 different ways to arrange the two digits.

To calculate the number of different plates of type KRIS followed by two additional digits, we can use the same logic as in Part A.

Part B: The first letter "K" of KRIS is fixed, so we have 1 option for the first letter. For the remaining three letters "RIS," we do not have any restrictions, so we have 26 options for each of them (assuming we consider only uppercase letters of the English alphabet). Finally, the two digits can be chosen from the numbers 0 to 9, as discussed in Part A.

Considering all these combinations, we have 1 * 26 * 26 * 26 * 10 * 10 = 1,757,600 different plates of type KRIS followed by two additional digits.