Asked by Taylor B
a. Use graphs to decide if the equation is an identity.
b. If the equation is not an identity, find a value of the variable that makes the equation false.
sin(pi/2+Beta)=1+sinBeta
b. If the equation is not an identity, find a value of the variable that makes the equation false.
sin(pi/2+Beta)=1+sinBeta
Answers
Answered by
Reiny
Without even graphing it, I can tell they are not an identity,
y = 1 + sinB would be the graph of y = sinB moved vertically by 1 unit
y = sin(B + π/2) would be the graph of y = sinB moved horizontally π/2 units to the left.
Two entirely different graphs.
test with π/2
LS = sin(π/2+π/2
= sin π = 0
RS = 1 + sin(π/2)
= 1 + 1 = 2 ≠ LS
y = 1 + sinB would be the graph of y = sinB moved vertically by 1 unit
y = sin(B + π/2) would be the graph of y = sinB moved horizontally π/2 units to the left.
Two entirely different graphs.
test with π/2
LS = sin(π/2+π/2
= sin π = 0
RS = 1 + sin(π/2)
= 1 + 1 = 2 ≠ LS
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