a. Use graphs to decide if the equation is an identity.

Question

b. If the equation is not an identity, find a value of the variable that makes the equation false.

sin(pi/2+Beta)=1+sinBeta

Answer 1

Without even graphing it, I can tell they are not an identity,

y = 1 + sinB would be the graph of y = sinB moved vertically by 1 unit

y = sin(B + π/2) would be the graph of y = sinB moved horizontally π/2 units to the left.

Two entirely different graphs.

test with π/2
LS = sin(π/2+π/2
= sin π = 0
RS = 1 + sin(π/2)
= 1 + 1 = 2 ≠ LS