Question

A worker sits at one end of a 183-N uniform rod that is 2.80 m long. A weight of 107 N is placed at the other end of the rod. The rod is balanced when the pivot is 0.670 m from the worker. Calculate the weight of the worker
W•0.67 = 183•(1.4-0.67) +107•(2.8-0.67)
W={183•0.73+107•2.13}/0.67=540 N

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