Asked by Eric
                Find and classify the relative maxima and minima of this function
f(x)= definite integral sign where a=0 and b=x.
t^2-4/(1+(cos^2(t)) dt
what should my value for u be? is it just t. not sure how to even tackle this problem.
            
        f(x)= definite integral sign where a=0 and b=x.
t^2-4/(1+(cos^2(t)) dt
what should my value for u be? is it just t. not sure how to even tackle this problem.
Answers
                    Answered by
            Eric
            
    Not sure how to get started. please help?
    
                    Answered by
            Steve
            
    The clue here is that we want to find extrema of f(x), which involves finding the derivative of f. Since f(x) is defined as an integral, we don't really have to do the integration. We just apply  the rules for differentiating under the integral sign. (See wikipedia, and scroll down for some examples)
f(x) = ∫[0,x] (t^2-4)/(1+(cos^2(t)) dt
so,
df/dx = (x^2-4)/(1+cos^2 x)
So, f'=0 when x^2-4 = 0, since the bottom is never zero.
Obviously the extrema are at x=2,-2.
    
f(x) = ∫[0,x] (t^2-4)/(1+(cos^2(t)) dt
so,
df/dx = (x^2-4)/(1+cos^2 x)
So, f'=0 when x^2-4 = 0, since the bottom is never zero.
Obviously the extrema are at x=2,-2.
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