Asked by Jody
X^2-2x-15/x^2+x-12*2x^2-6x/x^3+3x^2
Answers
Answered by
Reiny
Brackets are absolutely essential here.
I am sure you meant
(x^2-2x-15)/(x^2+x-12)*(2x^2-6x)/(x^3+3x^2)
= (x-5)(x+3)/( (x+4)(x-3) ) * 2x(x-3)/( x^2(x+3))
= 2(x-5)/(x(x+4)) or (2x -10)/(x^2 + 4x) , x ≠ ±3,0
I am sure you meant
(x^2-2x-15)/(x^2+x-12)*(2x^2-6x)/(x^3+3x^2)
= (x-5)(x+3)/( (x+4)(x-3) ) * 2x(x-3)/( x^2(x+3))
= 2(x-5)/(x(x+4)) or (2x -10)/(x^2 + 4x) , x ≠ ±3,0
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