Technically this is a VERY tough probem and can't be answered with the information given. However, I assume that the person making up the problem meant that 0.1 mol HCl was added to enough water to make 1L of solution.
(H^+) = (HCl) since HCl is 100% ionized.
(H^+) = 0.1 mols/1L = 0.1 M.
Then to find OH, use
(H^+)(OH^-) = Kw = 1E-14.
You know Kw and H^+, solve for OH^-
0.1 mol of HCl is added to 1 L of water.
What is [H+] and [OH-]?
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