Asked by Monica
Physicain elects to re-hydrate the patient br intravenous(IV) administration of 2.0 L of 0.45% (w/v) of NaCl. 0.45%9w/v) = 0.45g/100ml
A.How many grams of NaCl were given?
B.How many moles of Nacl were given?
C.What is the molarity of the NaCl solution?
A.How many grams of NaCl were given?
B.How many moles of Nacl were given?
C.What is the molarity of the NaCl solution?
Answers
Answered by
DrBob222
0.45 g NaCl x (2000/100) = ?g NaCl in 2 L.
mols NaCl = grams NaCl/molar mass NaCl.
M NaCl = mols NaCl/2L
mols NaCl = grams NaCl/molar mass NaCl.
M NaCl = mols NaCl/2L
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