Asked by stranger
Two point charges +q=1 μC and −q=−1 μC with mass m=1 g are fixed at the positions ±r⃗ 0 with |r0|=1 m. The charges are released from rest at t=0. Find the time τ in seconds at which they collide.Hint: Can you do it without integrating by using Kepler's laws?
1/4pienot =9 *10^9 m/F
1/4pienot =9 *10^9 m/F
Answers
Answered by
Elena
Coulomb’s Law:
F=k•q₁•q₂/r² =…
F=ma => a=F/m=…
r=at²/2
t=sqrt{2r/a)=…
F=k•q₁•q₂/r² =…
F=ma => a=F/m=…
r=at²/2
t=sqrt{2r/a)=…
Answered by
Ravi ANd Ashu
no not this way its accelaration is continuously increasing so integration is required......
Answered by
fhj
whats the answer
Answered by
Anonymous
what ia answer?please help.
Answered by
Answer..
0.74
Answered by
steven lou
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