Question

Suppose that blood flows through the aorta with a speed of 0.35 m/s. The cross-sectional area of the aorta is 2.0x10-4 m2. (a) Find the volume flow rate of the blood (b) The aorta branches into tens of thousands of capillaries whose total cross-sectional area is about 0.28 m2 .What is the average blood speed through them ?

Answer 1

rate (m^3/s) = speed (m/s) * area (m^2)
= 0.35 * 2.0*10^-4
= 0.70 * 10^-4
= 7.0 * 10^-5
= .0000070 m^3/s

7.0*10^-5 = v * .28
v = 25 * 10^-5
= 2.5 * 10^-4 m/s

Answer 2

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