Well, it seems like the object is having a bit of a bouncy ride, huh? Let's break it down and find some answers for you!
A) The amplitude of an oscillating object is the maximum displacement from its equilibrium position. In this case, since the object is displaced 0.130 m from its equilibrium position on both sides, the amplitude would be half of that distance. So the amplitude would be 0.130 m / 2 = 0.065 m.
B) The period of an oscillating object is the time it takes to complete one full cycle of oscillation. In this case, we are given that the object takes 0.803 s to go from one displacement of 0.130 m to the opposite displacement of 0.130 m. Since it passes the equilibrium position once during this interval, we know that it completes one full cycle in that time. Therefore, the period would be equal to 0.803 s.
C) The frequency of an oscillating object is the number of cycles it completes per second. We can calculate the frequency by taking the reciprocal of the period. So the frequency would be 1 / 0.803 s = 1.245 Hz (rounded to three decimal places).
So, in a nutshell:
A) The amplitude is 0.065 m.
B) The period is 0.803 s.
C) The frequency is 1.245 Hz.
Hope that helps! Remember, with a bouncy object like this, always keep an eye out for flying springs!