Asked by riya
for an aqueous solution having Calcl2 (2molar) and Mgcl2 (5molal) and specified gravity of solution is 1.145 calculate molality of chloride ion and molality if chloride ion.
Answers
Answered by
DrBob222
2 M CaCl2 = 2 mols CaCl2/L soln.
2 mol = 111 x 2 = 222 g (but that's an estimate--you recalculate it).
Use density to calculate mass of 1L soln. That will be 1145grams.
mass solvent = 1145g-222g = ?g and convert to kg. Then
mols Cl in CaCl2 = 4 (2*2)
mols Cl in MgCl2 = 10 (2*5)
Total mols Cl^- = 14
m Cl^- = mols Cl^-/kg solvent.
2 mol = 111 x 2 = 222 g (but that's an estimate--you recalculate it).
Use density to calculate mass of 1L soln. That will be 1145grams.
mass solvent = 1145g-222g = ?g and convert to kg. Then
mols Cl in CaCl2 = 4 (2*2)
mols Cl in MgCl2 = 10 (2*5)
Total mols Cl^- = 14
m Cl^- = mols Cl^-/kg solvent.
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