A uniform 5.9 T magnetic field points north.

Question

If an electron moves vertically downward (toward the ground) with a speed of 0.85 × 107
m/s through this field.
The charge on a proton is 1.60×10−19
.
a) What is the magnitude of the force acting
on it?
Answer in units of N

Answer 1

F=qvBsinα
sinα = sin180= 0 => F=0