Asked by Anonymous
How many moles of potassium hydroxide are required to neutralize 1.25 mol of phosphoric acid?
H3PO4 + 3KOH -> K3PO4 +3H2O
I got 0.42 mol KOH , is this correct?
thanks!
H3PO4 + 3KOH -> K3PO4 +3H2O
I got 0.42 mol KOH , is this correct?
thanks!
Answers
Answered by
DrBob222
Look at the equation.
1 mol H3PO4 = 3 mols KOH
So, 1.25 mol H3PO4 must need ?? mols KOH and it isn't 0.42.
1 mol H3PO4 = 3 mols KOH
So, 1.25 mol H3PO4 must need ?? mols KOH and it isn't 0.42.
Answered by
Anonymous
Okay, so I got 3.75 mol KOH now?
Answered by
DrBob222
Why do you think that is not right?
If 1 H3PO4 = 3 KOH, then
2 H3PO4 = 6 KOH and 1.25 must be somewhere between.
If 1 H3PO4 = 3 KOH, then
2 H3PO4 = 6 KOH and 1.25 must be somewhere between.
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