Question
What is the approximate molar fraction of ethanol c2h5oh in an aqueous solution in which the ethanol concentration is 11.0 molal?
A. 0.0011
B. 0.011
C. 0.170
D. 0.200
E. 0.600
A. 0.0011
B. 0.011
C. 0.170
D. 0.200
E. 0.600
Answers
I assume you mean mole fraction, XC2H5OH.
11 m means 11 mols C2H5OH/kg solvent or
11 mols/(11 mol C2H5OH + 1000 gH2O)
Convert 1000 g H2O to mols = about 55 but you need to do it more accurately.
Total mols = 11 + 55 = about 66
XC2H5OH = (11/66) = about 0.167.
11 m means 11 mols C2H5OH/kg solvent or
11 mols/(11 mol C2H5OH + 1000 gH2O)
Convert 1000 g H2O to mols = about 55 but you need to do it more accurately.
Total mols = 11 + 55 = about 66
XC2H5OH = (11/66) = about 0.167.
Related Questions
An aqueous solution of ethanol is 14.1M C2H5OH. The density of the solution is 0.853g/mL. What is...
A solution of ethanol (C2H5OH) is prepared by dissolving 35.0 ml of ethanol in enough water to make...
An aqueous solution contains 64g of ethanol( C2H5OH) in 122 grams of solution. The mole fraction of...
What is the mole fraction of ethanol, C2H5OH, in an aqueous solution that is 50.0% ethanol by mass?