Asked by Samm
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 C. The initial concentrations of Pb+2 and Cu+2 are 0.0500 M and 1.50 M, respectively.
A. What is the initial cell potential?
B. What is the cell potential when the concentration of Cu+2 has fallen to 0.200 M?
C. What are the concentrations of Pb+2 and Cu+2 when the cell potential falls to 0.35 V?
I answered A and B. For A I got: 0.43 V and for B I got 0.46 V. I cannot figure out part C though. I tried 0.35V=O.47V-((0.0592/2)*log(0.0500+X/1.50-X))but the answer doesn't seem right. I found X to equal 1. When I plug it all back in, it doesn't work though. Is my equation wrong? So confused...
A. What is the initial cell potential?
B. What is the cell potential when the concentration of Cu+2 has fallen to 0.200 M?
C. What are the concentrations of Pb+2 and Cu+2 when the cell potential falls to 0.35 V?
I answered A and B. For A I got: 0.43 V and for B I got 0.46 V. I cannot figure out part C though. I tried 0.35V=O.47V-((0.0592/2)*log(0.0500+X/1.50-X))but the answer doesn't seem right. I found X to equal 1. When I plug it all back in, it doesn't work though. Is my equation wrong? So confused...