Question
Consider the ellipse y^2=1-6 x^2.
Its vertices are (0,A) with A= ?
its foci are (0,+/-B) with B= ?
its eccentricity is ?
the length of its major axe is ?
the length of its minor axe is ?
Its vertices are (0,A) with A= ?
its foci are (0,+/-B) with B= ?
its eccentricity is ?
the length of its major axe is ?
the length of its minor axe is ?
Answers
Steve
put into standard form:
x^2/(1/6) + y^2 = 1
so, the major axis is vertical, and we have
a^2 = 1
b^2 = 1/6
c^2 = 5/6
recall that e=c/a
Given a,b,c you should have no trouble with foci and axis lengths
x^2/(1/6) + y^2 = 1
so, the major axis is vertical, and we have
a^2 = 1
b^2 = 1/6
c^2 = 5/6
recall that e=c/a
Given a,b,c you should have no trouble with foci and axis lengths