Asked by Nicole
What is the mass of ethylene gycol dissolved in 5.00 kg of a 40.0% solution?
Answers
Answered by
DrBob222
40% (by mass) means 40g solute/100 g solution.
40 x (6000/100) = ?
40 x (6000/100) = ?
Answered by
Mrittika3278
Answer:
3kg
Explanation:
HI friend!
Step 1 -
The Antifreeze solution lowers the freezing point of a water-based liquid.
It is composed of ethyl alcohol(solute) and water(solvent)
Step 2 -
Second, 40% Antifreeze solution means---
40% solute is present in 100 kg of Antifreeze solution.
And here, the solute is ethyl alcohol - 40kg
Step 3-
So, wate(solvent) would become= 100-40 = 60 kg
Therefore we can say that- in 100 kg of Antifreeze solution there is 60 kg water.
Step 4 - (Calculation)
Antifreeze Solution H2O
100 60
5 60/100 * 5 = 3 kg
(The above numerical means that-
If there is 100 kg of the solution, there is 60 kg of water
So, 5kg of the solution, there is 60/100 * 5 = 3kg water)
3kg
Explanation:
HI friend!
Step 1 -
The Antifreeze solution lowers the freezing point of a water-based liquid.
It is composed of ethyl alcohol(solute) and water(solvent)
Step 2 -
Second, 40% Antifreeze solution means---
40% solute is present in 100 kg of Antifreeze solution.
And here, the solute is ethyl alcohol - 40kg
Step 3-
So, wate(solvent) would become= 100-40 = 60 kg
Therefore we can say that- in 100 kg of Antifreeze solution there is 60 kg water.
Step 4 - (Calculation)
Antifreeze Solution H2O
100 60
5 60/100 * 5 = 3 kg
(The above numerical means that-
If there is 100 kg of the solution, there is 60 kg of water
So, 5kg of the solution, there is 60/100 * 5 = 3kg water)
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