To prepare 1.000 kg of 5.5 percent by mass KCl (aq), one may dissolve

Question

a. 994.5 g KCl in 5.5 g of water
b. 5.5 g KCl in 994.5 g of water
c. 5.5 g KCl in 1000.0 g of water
d. 55 g KCl in 945 g of water
e. 55.0 g KCl in 1000.0 g of water

Answer 1

5.5% by mass means
5.5 g KCl + 94.5 g H2O = 100 g solution.
Just multiply by 10 to obtain
55 g KCl + 945 g H2O = 1,000 g solution.

Answer 2

thanks