Asked by RainbowGlitter
Assuming that the heights of college women are normally distributed with mean 66 inches and standard deviation 2 inches, what percentage of women are shorter than 72 inches?
Answers
Answered by
MathGuru
Try z-scores:
z = (x - mean)/sd
x = 72
mean = 66
sd = 2
Calculate the z-score, then check a z-table for your probability (remember the question is asking "what percentage of women are shorter than 72 inches" when looking at the table).
z = (x - mean)/sd
x = 72
mean = 66
sd = 2
Calculate the z-score, then check a z-table for your probability (remember the question is asking "what percentage of women are shorter than 72 inches" when looking at the table).
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