if f(x) = 3^g(x)
then f'(x) = (ln3)(3^(gx)) (g ' (x) )
g(x) = ???? , do you mean 3 to be the base of LOG
or are we doing ln ? or what
Once you have decided, continue as below ...
so g ' (x) = ....
insert that result above.
Find f’(x) if f(x) = 3^g(x) where g(x) = LOG_3(x^2 - √x + 4/x + 10*LOG_e(x))
3 answers
the 3 is the base so log(base3)(...log(base/e)(x)
if g(u) = log_3(u)
f(x) = 3^g(u) = 3^log_3(u) = u
so now it's easy:
f(x) = x^2 - √x + 4/x + 10*ln(x)
f'(x) = 2x - 1/(2√x) - 4/x^2 + 10/x
f(x) = 3^g(u) = 3^log_3(u) = u
so now it's easy:
f(x) = x^2 - √x + 4/x + 10*ln(x)
f'(x) = 2x - 1/(2√x) - 4/x^2 + 10/x
1 answer