Asked by Matt
The question is; identify the center and the radius of the circle in this equation.
3x^2 - √ 3x + 3y^2 - y + 1/12 = 0
I ended up getting
C:(√ 3/6, 1/6)
and
R: √ 3/6
3x^2 - √ 3x + 3y^2 - y + 1/12 = 0
I ended up getting
C:(√ 3/6, 1/6)
and
R: √ 3/6
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