Asked by alexia
Four times the sum of the number of reds and blue exceeded 3 times the number of whites by 3. Five times the sum of the number of blues and whites exceeded 8 times the number of reds by 13. If there were 5 more whites than blues, how many of each color were there?
Answers
Answered by
Steve
just put the clues into symbols:
4(r+b) = 3w+3
5(b+w) = 8r+13
w = b+5
now substitute for w in the 1st two equations:
4(r+b) = 3(b+5)+3
5(b+b+5) = 8r+13
or,
4r + b = 18
8r - 10b = 12
8r - 10(18-4r) = 12
48r = 192
r = 4
so, b=2 and w=7
4(r+b) = 3w+3
5(b+w) = 8r+13
w = b+5
now substitute for w in the 1st two equations:
4(r+b) = 3(b+5)+3
5(b+b+5) = 8r+13
or,
4r + b = 18
8r - 10b = 12
8r - 10(18-4r) = 12
48r = 192
r = 4
so, b=2 and w=7
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