Find dy/dx by implicit differentiation for x^2 - 2xy + y^3 = C

Answer 1

x^2 - 2xy + y^3 = C
2x - 2y - 2xy' + 3y^2 y' = 0
y'(3y^2 - 2x) = 2(y-x)

y' = 2(y-x)/(3y^2 - 2x)