Asked by Renee
One of the concrete pillars that support a house is 2.1 m tall and has a radius of 0.35 m. The density of concrete is about 2.2 103 kg/m3. Find the weight of this pillar in pounds (1 N = 0.2248 lb).
Answers
Answered by
Henry
V=pi*r^2 * h=3.14*0.35^2 * 2.1=0.8o8 m^3
Mass = 0.808 m^3 * 2200kg/m*3=1777.1 kg.
Wt. = 1777.1kg * 1Lb/0.454kg = 3914 Lbs.
Mass = 0.808 m^3 * 2200kg/m*3=1777.1 kg.
Wt. = 1777.1kg * 1Lb/0.454kg = 3914 Lbs.
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