Question
At a point 16 yards from the base of a tower,the distance to the top of the tower is 4 ysrds more than the height of the tower.Find the height of the tower.
Answers
looks like a regular Pythagorean problem
Height of tower --- x
hypotenuse ---- x+4
base ----- 16
x^2 + 16^2 = (x+4)^2
x^2 = 256 = x^2 + 8x + 16
240 = 8x
x = 30
Height of tower --- x
hypotenuse ---- x+4
base ----- 16
x^2 + 16^2 = (x+4)^2
x^2 = 256 = x^2 + 8x + 16
240 = 8x
x = 30
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