Asked by Gabe
find all ssymptotes of indicated type.
I am really confused on this one.
f(x)=(x-9)/(x^2-4), vertical
x^2-4=0 x=+-2 x=2&x=-2
x arrow oo or x arrow -oo
(-9/x)&(-4/x) approach 0
h(x)=(1/x)+0)/(1+0)=(0/1)=0
I am really confused on this one.
f(x)=(x-9)/(x^2-4), vertical
x^2-4=0 x=+-2 x=2&x=-2
x arrow oo or x arrow -oo
(-9/x)&(-4/x) approach 0
h(x)=(1/x)+0)/(1+0)=(0/1)=0
Answers
Answered by
Anonymous
Hmm is it asking you to find only the vertical asymptotes? If so than you got them. The function has a vertical asymptote at -2 and 2. If you also have to find a horizontal asymptote than its 0 because the denominator has the highest power.
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