one company charges $6.95 per shirt plus a setup fee of $43. Another company charges $8.40 per shirt plus a $58 set up fee. for what number of shirts would the total be the same?

User Icon for PsyDAG PsyDAG answered
11 years ago

43 + 6.95n = 58 + 8.40n

Solve for n.

User Icon for Hi-tech Hi-tech answered
8 years ago

subtract 43 from both sides

9.65n=58-43+8.40n
9.65n=15+8.40n
subtract 8.40n from both sides
9.65n-8.40n=15
1.25n=15
divide it by 1.25
n=12
go back to the equation and plug in
12
9.65(12)+43=8.40(12)+58
158.8=158.8
There are infinity many solutions to this problem

User Icon for CAMDEN EZ CAMDEN EZ answered
4 years ago

Company A charges $9.65 per shirt plus a setup fee of $43. Company B charges $8.40 per shirt plus a $58 fee.

Can you help me with this problem?

User Icon for Anonymous Anonymous answered
3 years ago

168

User Icon for Explain Bot Explain Bot answered
1 year ago

To find the number of shirts for which the total cost is the same for both companies, we can set up an equation and solve for the unknown number of shirts.

Let's assume the number of shirts is represented by the variable "x."

For the first company, the total cost can be calculated as follows:
Total cost = (Cost per shirt * Number of shirts) + Setup fee
Total cost = (6.95 * x) + 43

For the second company, the total cost can be calculated as follows:
Total cost = (Cost per shirt * Number of shirts) + Setup fee
Total cost = (8.40 * x) + 58

Now, we can set up an equation to find the value of x for which the total cost is the same for both companies:

(6.95 * x) + 43 = (8.40 * x) + 58

Simplifying the equation:

6.95x + 43 = 8.40x + 58

Rearranging the terms:

8.40x - 6.95x = 58 - 43

1.45x = 15

Finally, we can solve for x by dividing both sides of the equation by 1.45:

x = 15 / 1.45

x โ‰ˆ 10.34

Therefore, the total cost would be the same for approximately 10 shirts from both companies. Since we can't have a fraction of a shirt, we would need to round up to the nearest whole number. So, for the total cost to be the same, we would need to order at least 11 shirts.