what mass of 25% ba(n03)2 solution contain 40 grams of ba(n03)2 ?
Answer 160g
My calculation
40g/261.37g/mol = 0.15305/0.25g = 0.612
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Answer 160g
My calculation
40g/261.37g/mol = 0.15305/0.25g = 0.612
This answer is not right
Who helps