Asked by Touch
A sample of ideal gas is in a sealed container. The pressure of the gas is 675torr , and the temperature is 28\, ^{\circ}C . If the temperature changes to 91\, ^{\circ}C with no change in volume or amount of gas, what is the new pressure, P_2, of the gas inside the container?
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Answered by
Elena
p₂=p₁T₂/T₁
p₁=675 torr = 89992.35 Pa
T ₁=273+28 =301 K
T₂ = 273+ 91= 364 K
p₁=675 torr = 89992.35 Pa
T ₁=273+28 =301 K
T₂ = 273+ 91= 364 K
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