Asked by Anonymous
two people carry a heavy electric motor by placing it on a light board 2m long.one person lifts at one end with a force of 700N, and the other lifts the opposite end with a force of 400N.Calculate the weight of the motor and determine where its center of Gravity is Located
Answers
Answered by
Elena
The sums of torques respectively the edges of the board are:
W•x-400•2 = 0
W• (2-x) -700•2=0
W•x=800
2W-W•x -1400 = 0
2W-800-1400=0
W=1100 N
x=800/W =0.73 m
W•x-400•2 = 0
W• (2-x) -700•2=0
W•x=800
2W-W•x -1400 = 0
2W-800-1400=0
W=1100 N
x=800/W =0.73 m
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